1
NEET 2017
MCQ (Single Correct Answer)
+4
-1
Change Language
The acceleration due to gravity at a height at a height 1 km above the rearth is the same as at a depth d below the surface of earth. Then
A
d = 1 km
B
d = $${3 \over 2}$$ km
C
d = 2 km
D
d = $${1 \over 2}$$ km
2
NEET 2016 Phase 2
MCQ (Single Correct Answer)
+4
-1
Change Language
A satellite of mass m is orbiting the earth (of radius R) at a height h from its surface. The total energy of the satellite in terms of g0, the value of acceleration due to gravity at the earth's surface, is
A
$${{m{g_0}{R^2}} \over {2\left( {R + h} \right)}}$$
B
$$ - {{m{g_0}{R^2}} \over {2\left( {R + h} \right)}}$$
C
$${{2m{g_0}{R^2}} \over {R + h}}$$
D
$$ - {{2m{g_0}{R^2}} \over {R + h}}$$
3
NEET 2016 Phase 2
MCQ (Single Correct Answer)
+4
-1
Change Language
Starting from the centre of the earth having radius R, the variation of g (acceleration due to gravity) is shown by
A
NEET 2016 Phase 2 Physics - Gravitation Question 59 English Option 1
B
NEET 2016 Phase 2 Physics - Gravitation Question 59 English Option 2
C
NEET 2016 Phase 2 Physics - Gravitation Question 59 English Option 3
D
NEET 2016 Phase 2 Physics - Gravitation Question 59 English Option 4
4
NEET 2016 Phase 1
MCQ (Single Correct Answer)
+4
-1
Change Language
The ratio of escape velocity at earth (ve) to the escape velocity at a planet (vp) whose radius and mean density are twice as that of earth is
A
1 : 4
B
1 : $$\sqrt 2 $$
C
1 : 2
D
1 : 2$$\sqrt 2 $$
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