At what height from the surface of earth the gravitation potential and the value of g are $$-$$5.4 $$ \times $$ 10⁷ J kg^$$-$$1 and 6.0 m s^$$-$$2 respectively? Take the radius of earth as 6400 km.

A remote-sensing satellite of earth revolves in a circular orbit at a height of 0.25 $$ \times $$ 10⁶ m above the surface of earth. If earth's radius is 6.38 $$ \times $$ 10⁶ m and g = 9.8 ms^$$-$$2, then the orbital speed of the satellite is

A satellite S is moving in an elliptical orbit around the earth. The mass of the satellite is very small compared to the mass of the earth. Then,

Kepler's third law states that square of period of revoluation (T) of a planet around the sun, is proportional to third power of average distance r between sun and planet i.e. T² = Kr³ here K is constant. If the masses of sun and planet are M and m respectively then as per Newton's law of gravitation force of attraction between them is F = $${{GMm} \over {{r^2}}}$$, here G is gravitational constant. The relation between G and K is described as