AIPMT 2010 Mains | Gravitation Question 41 | Physics

AIPMT 2010 Mains

MCQ (Single Correct Answer)

-1

The additional kinetic energy to be provided to a satellite of mass m revolving around a planet of mass M, to transfer it from a circular orbit of radius R₁ to another of radius R₂(R₂ > R₁) is

GmM $$\left( {{1 \over {R_1^2}} - {1 \over {R_2^2}}} \right)$$

GmM $$\left( {{1 \over {{R_1}}} - {1 \over {{R_2}}}} \right)$$

2GmM $$\left( {{1 \over {{R_1}}} - {1 \over {{R_2}}}} \right)$$

$${1 \over 2}$$GmM $$\left( {{1 \over {{R_1}}} - {1 \over {{R_2}}}} \right)$$

AIPMT 2010 Prelims

MCQ (Single Correct Answer)

-1

A particle of mass M is situated at the centre of a spherical shell of same mass and radius a. The magnitude of the gravitational potential at a point sutuated at a/2 distance from the centre, will be :

$${{GM} \over a}$$

$${{2GM} \over a}$$

$${{3GM} \over a}$$

$${{4GM} \over a}$$

AIPMT 2010 Prelims

MCQ (Single Correct Answer)

-1

The radii of circular orbits of two satellites A and B of the earth, are 4R and R, respectively. If the speed of satellite A is 3V, then the speed of satellite B will be

$${{3V} \over 4}$$

6$$V$$

12$$V$$

$${{3V} \over 2}$$

AIPMT 2010 Prelims

MCQ (Single Correct Answer)

-1

A man of 50 kg mass is standing in a gravity free space at a height of 10 m above the floor. He throws a stone of 0.5 kg mass downwards with a speed 2 m/s. When the stone reaches the floor, the distance of the man above the floor will be

9.9 m

10.1 m

10 m

20 m

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