AIPMT 2015 | Current Electricity Question 44 | Physics

AIPMT 2015

MCQ (Single Correct Answer)

-1

A potentiometer wire of length L and a resistance r are connected in series with a battery of e.m.f. E₀ and a resistance r₁. An unknown e.m.f. E is balanced at a length $$l$$ of the potentiometer wire. The e.m.f. E will be given by

$${{{E_0}l} \over L}$$

$${{L{E_0}r} \over {\left( {r + {r_1}} \right)l}}$$

$${{L{E_0}r} \over {l{r_1}}}$$

$${{{E_0}r} \over {\left( {r + {r_1}} \right)}}.{l \over L}$$

AIPMT 2015

MCQ (Single Correct Answer)

-1

A circuit contains an ammeter, a battery of 30 V and a resistance 40.8 ohm all connected in series. If the ammeter has a coil of resistance 480 ohm and a shunt of 20 ohm, the reading in the ammeter will be

0.5 A

0.25 A

AIPMT 2015

MCQ (Single Correct Answer)

-1

Two metal wires of identical dimensions are connected in series. If $$\sigma $$₁ and $$\sigma $$₂ are the conductivity of the combination is

$${{{\sigma _1} + {\sigma _2}} \over {{\sigma _1}{\sigma _2}}}$$

$${{{\sigma _1}{\sigma _2}} \over {{\sigma _1} + {\sigma _2}}}$$

$${{2{\sigma _1}{\sigma _2}} \over {{\sigma _1} + {\sigma _2}}}$$

$${{{\sigma _1} + {\sigma _2}} \over {2{\sigma _1}{\sigma _2}}}$$

AIPMT 2015 Cancelled Paper

MCQ (Single Correct Answer)

-1

A potentiometer wire has length 4 m and resistance 8 $$\Omega $$. The resistance that must be connected in series with the wire and an accumulator of e.m.f. 2 V, so as to get a potential gradient 1 mV per cm on the wire is

44 $$\Omega $$

48 $$\Omega $$

32 $$\Omega $$

40 $$\Omega $$

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