AIPMT 2009 | Current Electricity Question 70 | Physics

AIPMT 2009

MCQ (Single Correct Answer)

-1

A student measures the terminal potential difference (V) of a cell (of emf $$\varepsilon $$ and internal resistance r) as a function of the current (I) flowing through it. The slope, and intercept, of the graph between V and I, then respectively, equal

$$-$$ r and $$\varepsilon $$

r and $$-$$ $$\varepsilon $$

$$-$$ $$\varepsilon $$ and r

$$\varepsilon $$ and $$-$$ r

AIPMT 2009

MCQ (Single Correct Answer)

-1

The mean free path of electrons in a metal is 4 $$ \times $$ 10^$$-$$8 m. The electric field which can give on an average 2 eV energy to an electron in the metal will be in units V/m

$$5 \times {10^{ - 11}}$$

8 $$ \times $$ 10^$$-$$11

5 $$ \times $$ 10⁷

8 $$ \times $$ 10⁷

AIPMT 2009

MCQ (Single Correct Answer)

-1

A wire of resistance 12 ohms per meter is bent to form a complete circle of radius 10 cm. The resistance between its two diametrically opposite points, A and B as shown in the figure is

AIPMT 2009 Physics - Current Electricity Question 75 English

AIPMT 2009 Physics - Current Electricity Question 75 English

$$3\,\Omega $$

$$6\pi \,\Omega $$

$$6\,\Omega $$

$$0.6\pi \,\Omega $$

AIPMT 2009

MCQ (Single Correct Answer)

-1

See the electrical circuit shown in this figure. Which of the following equations is a correct equation for it ?

AIPMT 2009 Physics - Current Electricity Question 76 English

AIPMT 2009 Physics - Current Electricity Question 76 English

$${\varepsilon _2} - {i_2}{r_2} - {\varepsilon _1} - {i_1}{r_1} = 0$$

$$ - {\varepsilon _2} - \left( {{i_1} + {i_2}} \right)R + {i_2}{r_2} = 0$$

$${\varepsilon _1} - \left( {{i_1} + {i_2}} \right)R + {i_1}{r_1} = 0$$

$${\varepsilon _1} - \left( {{i_1} + {i_2}} \right)R - {i_1}{r_1} = 0$$

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