Two electrolytic cells are connected in series containing $\mathrm{CuSO}_4$ solution and molten $\mathrm{AlCl}_3$. If in electrolysis 0.4 moles of 'Cu' are deposited on cathode of first cell. The number of moles of 'Al' deposited on cathode of the second cell is

The resistance of $\frac{1}{10} M$ solution is $25 \times 10^3$ ohm. What is the molar conductivity of solution? (cell constant $=1.25 \mathrm{~cm}^{-1}$)