MHT CET 2024 3rd May Evening Shift | Electrochemistry Question 34 | Chemistry

The limiting molar conductivities $\left(\Lambda_0\right)$ for NaCl , KBr and KCl are 126,152 and $150 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$ respectively. What is the $\Lambda_0$ of NaBr ?

$128 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$

$302 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$

$278 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$

$176 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$

MHT CET 2024 3rd May Evening Shift

MCQ (Single Correct Answer)

-0

A conductivity cell dipped on 0.05 M KCl has resistance 600 ohm. If conductivity is $0.0015 \mathrm{ohm}^{-1} \mathrm{~cm}^{-1}$. What is the value of cell constant?

$0.47 \mathrm{~cm}^{-1}$

$0.90 \mathrm{~cm}^{-1}$

$1.5 \mathrm{~cm}^{-1}$

$2.5 \mathrm{~cm}^{-1}$

MHT CET 2024 3rd May Evening Shift

MCQ (Single Correct Answer)

-0

What is the cell constant, if two platinum electrodes in conductivity cell are separated by 0.92 cm and area of cross section is $1.2 \mathrm{~cm}^2$ ?

$0.767 \mathrm{~cm}^{-1}$

$0.906 \mathrm{~cm}^{-1}$

$1.304 \mathrm{~cm}^{-1}$

$1.104 \mathrm{~cm}^{-1}$

MHT CET 2024 3rd May Morning Shift

MCQ (Single Correct Answer)

-0

The molar conductivity of 0.02 M KCl solution is $410 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$ at $25^{\circ} \mathrm{C}$. Calculate its conductivity?

$8.2 \times 10^{-3} \Omega^{-1} \mathrm{~cm}^{-1}$

$2.8 \times 10^{-3} \Omega^{-1} \mathrm{~cm}^{-1}$

$4.1 \times 10^{-3} \Omega^{-1} \mathrm{~cm}^{-1}$

$5.4 \times 10^{-3} \Omega^{-1} \mathrm{~cm}^{-1}$

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