MHT CET 2021 23th September Morning Shift | Electrochemistry Question 47 | Chemistry

The conductivity of $$0.3 \mathrm{M}$$ solution of $$\mathrm{KCl}$$ at $$298 \mathrm{~K}$$ is $$0.0627 \mathrm{~S} \mathrm{~cm}^{-1}$$. What is it's molar conductivity?

$$104 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$$

$$188 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$$

$$209 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$$

$$109 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$$

MHT CET 2021 23th September Morning Shift

MCQ (Single Correct Answer)

-0

In the cell represented as $$\mathrm{Ni}_{(\mathrm{s})}\left|\mathrm{Ni}_{(\mathrm{IM})}^{2 \oplus}\right|\left|\mathrm{Ag}_{(\mathrm{IM})}^{\oplus}\right| \mathrm{Ag}_{(\mathrm{s})}$$, the reducing agent is

$$\mathrm{Ag}^{\oplus}$$

$$\mathrm{Ni}$$

$$\mathrm{Ni}^{2 \oplus}$$

MHT CET 2021 22th September Evening Shift

MCQ (Single Correct Answer)

-0

How many Faraday of electricity is required to deposit $$0.8 \mathrm{~g}$$ of calcium at cathode by the electrolysis of $$\mathrm{CaCl}_2$$ ?

(Molar mass of $$\mathrm{Ca}=40 \mathrm{~g} \mathrm{~mol}^{-1}$$)

4 F

0.04 F

2.5 F

2 F

MHT CET 2021 22th September Evening Shift

MCQ (Single Correct Answer)

-0

What is the conductivity of $$0.02 \mathrm{~M} \mathrm{~KCl}$$ solution if cell constant is $$1.29 \mathrm{~cm}^{-1}$$ with resistance 645 $$\Omega$$ ?

$$5.0 \times 10^{-3} \Omega^{-1} \mathrm{~cm}^{-1}$$

$$2.0 \times 10^{-3} \Omega^{-1} \mathrm{~cm}^{-1}$$

$$8.3 \times 10^{-3} \Omega^{-1} \mathrm{~cm}^{-1}$$

$$2.5 \times 10^{-3} \Omega^{-1} \mathrm{~cm}^{-1}$$

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