The area bounded by the curve $$y=\cos x, x=0$$ and $$x=\pi$$ is

The area of the region (in sq units) bounded by the curve $$ y=\sqrt{16-x^2} \text { and } x \text {-axis is } $$

$$ \text { The area of the region (in square units) bounded by the line } y+3=x ; x=1 \text { and } x=5 \text { is } $$

The area of the upper half of the circle whose equation is $$(x-1)^2+y^2=1$$ is given by