Area Under The Curves · Mathematics · COMEDK
MCQ (Single Correct Answer)
The area enclosed by the curve $y=-x^2$ and the line $x+y+2=0$ is
Find the area bounded by the curve $y=|2-x|$, the $x$-axis, and the lines $x=0$ and $x=5$
The area of the region bounded by the line $y=x+2$ and the curve $x=-y^2$ is
The area of the region in the first quadrant enclosed by the $x$-axis, the line $x=\sqrt{3} y$ and the circle $x^2+y^2=4$ is
The area bounded by the curve $$y=\cos x, x=0$$ and $$x=\pi$$ is
The area of the region (in sq units) bounded by the curve $$ y=\sqrt{16-x^2} \text { and } x \text {-axis is } $$
$$ \text { The area of the region (in square units) bounded by the line } y+3=x ; x=1 \text { and } x=5 \text { is } $$
The area of the upper half of the circle whose equation is $$(x-1)^2+y^2=1$$ is given by
The area bounded by the curve $$y^2=4 a^2(x-1)$$ and the lines $$x=1, y=4 a$$ is
The area enclosed by the pair of lines $$xy=0$$, the line $$x-4=0$$ and $$y+5=0$$ is
The area bounded by the curve $$x=4-y^2$$ and the Y-axis is