The area of the region (in sq units) bounded by the curve $$ y=\sqrt{16-x^2} \text { and } x \text {-axis is } $$

$$ \text { The area of the region (in square units) bounded by the line } y+3=x ; x=1 \text { and } x=5 \text { is } $$

The area of the upper half of the circle whose equation is $$(x-1)^2+y^2=1$$ is given by

The area bounded by the curve $$y^2=4 a^2(x-1)$$ and the lines $$x=1, y=4 a$$ is