If the area under the curve $y=\sqrt{a^2-x^2}$ included between the lines $x=0$ and $x=a$ is 4 sq units. Then the value of ' $a$ ' is

The area of the region enclosed by the lines $2 x+y=10, y=1, y=5$ and the $y$-axis is

Area of the region bounded by the curve $y=\sin \left(\frac{x}{2}\right)$ between $-4 \pi$ and 0 is

The area bounded by the parabola $y^2=36 x$ and its latus rectum is