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MCQ (Single Correct Answer)

COMEDK 2023 Morning Shift
If $$z=\sqrt{3}+i$$, then the argument of $$z^2 e^{z-i}$$ is equal to
COMEDK 2023 Morning Shift
If $$i=\sqrt{-1}$$ and $$n$$ is a positive integer, then $$i^n+i^{n+1}+i^{n+2}+i^{n+3}$$ is equal to
COMEDK 2023 Morning Shift
If $$\left(\frac{3}{2}+i \frac{\sqrt{3}}{2}\right)^{50}=3^{25}(x+i y)$$, where $$x$$ and $$y$$ are real, then the ordered pair $$(2 x, 2 y)$$ is...
COMEDK 2023 Evening Shift
If the conjugate of $$(x+i y)(1-2 i)$$ be $$1+i$$, then
COMEDK 2022
The argument of $${{1 - i\sqrt 3 } \over {1 + i\sqrt 3 }}$$ is
COMEDK 2022
Evaluate $${\left[ {{i^{22}} + {{\left( {{1 \over i}} \right)}^{25}}} \right]^3}$$
COMEDK 2022
$${(i + \sqrt 3 )^{100}} + {(i - \sqrt 3 )^{100}} + {2^{100}}$$ is equal to
COMEDK 2021
What is the argument of the complex number $${{(1 + i)(2 + i)} \over {3 - i}}$$, where $$i = \sqrt { - 1} $$ ?
COMEDK 2021
Evaluate $${\left[ {{i^{18}} + {{\left( {{1 \over i}} \right)}^{25}}} \right]^3}$$.
COMEDK 2021
If $${(\sqrt 3 + i)^{100}} = {2^{99}}(a + ib)$$, then $${a^2} + {b^2}$$ is equal to
COMEDK 2020
The conjugate of the complex number $${{{{(1 + i)}^2}} \over {1 - i}}$$ is
COMEDK 2020
The imaginary part of $$i^i$$ is
COMEDK 2020
The amplitude of $${(1 + i)^5}$$ is
COMEDK 2020
If $$1,\omega ,{\omega ^2}$$ are the cube roots of unity, then $$(1 + \omega )(1 + {\omega ^2})(1 + {\omega ^4})(1 + {\omega ^8})$$ is equal to
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