Haloalkanes and Haloarenes · Chemistry · COMEDK

Identify the final product $[Z]$ formed when Chlorobenzene undergoes the given series of reactions:

Both reactions (i) and (ii) give the same compound X as the major product. Identify X

(i). 3-Methylbut-1-ene $+\mathrm{HCl} \rightarrow \mathrm{X}$

(ii). Neopentyl alcohol $+\mathrm{HCl}\left(\right.$ anh. $\left.\mathrm{ZnCl}_2\right) \rightarrow \mathrm{X}$

Identify the compound which gives an optically active haloalkane on reaction with $\mathrm{H}_2$ / Ni on heating.

A	B	C	D

Identify the final product formed when Toluene undergoes a series of reactions with reagents given in the order:

(i) $$\mathrm{Cl}_2$$ / Sunlight

(ii) $$\mathrm{H}_2 \mathrm{O} / 373 \mathrm{~K}$$

(iii) Acetophenone / $$\mathrm{OH^-}$$ at $$293 \mathrm{~K}$$

Arrange the following compounds in the increasing order of their reactivity when each of them is reacted with chloroethane / anhydrous AlCl$$_3$$.

Match the names of reactions given in Column I with the appropriate reactions given in Column II.

Arrange the compounds $$\mathrm{A}, \mathrm{B}, \mathrm{C}$$ and $$\mathrm{D}$$ in the increasing order of their reactivity towards $$\mathrm{S_N}1$$ reaction.

$$ \begin{aligned} & \mathrm{A}=\mathrm{C}_6 \mathrm{H}_5 \mathrm{CH}_2 \mathrm{Cl} \\ & \mathrm{B}=\mathrm{C}_6 \mathrm{H}_5 \mathrm{Cl} \\ & \mathrm{C}=\mathrm{CH}_2=\mathrm{CH}-\mathrm{Cl} \\ & \mathrm{D}=\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{Cl} \end{aligned}$$

Identify the products C, D and F formed in the following sets of reactions.

Arrange the following compounds in the decreasing order of reactivity towards electrophilic substitution reaction.

(I) Chlorobenzene

(II) Nitrobenzene

(III) Benzene

(IV) Isopropylbenzene

Arrange the following in the order of increasing reactivity towards $$\mathrm{SN}_{\mathrm{2}}$$ reactions.

$$\begin{array}{ll} \left(\mathrm{CH}_3\right)_3 \mathrm{CCH}_2 \mathrm{Br}(\mathrm{P}) ; & \\\mathrm{CH}_3\left(\mathrm{CH}_2\right)_3 \mathrm{Br}(\mathrm{Q}) ; &\\ \mathrm{CH}_3 \mathrm{CH}_2-\mathrm{CH}\left(\mathrm{CH}_3\right)-\mathrm{CH}_2 \mathrm{Br}(\mathrm{R}) ; & \\\left(\mathrm{CH}_3\right)_2 \mathrm{CHCH}_2 \mathrm{CH}_2 \mathrm{Br}(\mathrm{S}) \end{array}$$

Choose the incorrect statement from the following.

Consider the following reaction

$$(\mathrm{CH}_3)_2 \mathrm{CHCH}_2 \mathrm{Br}+(\mathrm{CH}_3)_3 \mathrm{CCH}_2 \mathrm{Br} \xrightarrow[\Delta]{\mathrm{Na} \text { /dry ether }} \mathrm{X}+\mathrm{Y}+\mathrm{Z}$$

Identify the product which is not formed?

The major product obtained in the following reaction is :

Which one of the following compounds when reacted with $$\mathrm{NaOH}$$ (aq) undergoes Substitution Nucleophilic Bimolecular reaction with retention of configuration?

$$t$$-butyl chloride preferably undergo hydrolysis by

In Friedal-Crafts alkylation reaction of phenol with chloromethane, the product formed will be

Identify A, B and C.

Identify the compounds A, B, C and D.

$$ \text { 1,2,2,2-tetrachloroethane } \xrightarrow[\Delta]{\mathrm{Zn}}[\mathrm{A}] $$

[A] $$ \xrightarrow[675 \mathrm{~K}]{\text { Fe tube }} $$ [B] $$ \xrightarrow[\text { Conc. } \mathrm{H}_2 \mathrm{SO}_4]{\text { Conc. } \mathrm{HNO}_3} $$ [C] $$ \xrightarrow[\text { Anhydrous } \mathrm{AlCl}_3]{\mathrm{Cl} /}$$ [D]

The reactions taking place with $$\mathrm{2- Phenyl-2-bromopropane}$$ as the starting material is shown below. Identify [A] and [B] formed in the reaction.

$$ \mathrm{C}_6 \mathrm{H}_5-\mathrm{C}\left(\mathrm{CH}_3\right)_2^{-} \mathrm{Br} \xrightarrow[\Delta]{\text { KOH Alcoholic }}[\mathrm{A}] $$

$$ [\mathrm{A}]+\mathrm{HBr} \xrightarrow{\left(\mathrm{C}_6 \mathrm{H}_5 \mathrm{CO})_2 \mathrm{O}\right.}[\mathrm{B}]$$

Which one of the following will undergo Nucleophilic substitution, by $$\mathrm{S}_{\mathrm{N}}{ }^1$$ mechanism, fastest?

Alkyl halides undergoing S_N2 reaction do inverse

The reaction $$\mathrm{ArN_2^ + C{l^ - }\buildrel {Cu/HCl} \over \longrightarrow ArCl + {N_2} + CuCl}$$ is called as

Benzene reacts with chlorine in sunlight to give a final product

An alkyl halide reacts with alcoholic ammonia in a sealed tube, the product formed will be