MHT CET 2023 14th May Morning Shift | Electrochemistry Question 5 | Chemistry

Calculate molar conductivity of $$\mathrm{NH}_4 \mathrm{OH}$$ at infinite dilution if molar conductivities of $$\mathrm{Ba}(\mathrm{OH})_2$$ $$\mathrm{BaCl}_2$$ and $$\mathrm{NH}_4 \mathrm{Cl}$$ at infinite dilution are $$520,280,129 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$$ respectively.

$$249.0 ~\Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$$

$$498.0 ~\Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$$

$$125.0 ~\Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$$

$$369.0 ~\Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$$

MHT CET 2023 13th May Evening Shift

MCQ (Single Correct Answer)

-0

Which from the following expression represents molar conductivity of an electrolyte $$\mathrm{A}_2 B_3$$ type?

$$2 \lambda_{A^{+++}}^0+3 \lambda_{B^{--}}^0$$

$$3 \lambda_{A^{+++}}^0+2 \lambda_{B^{--}}^0$$

$$2 \lambda_{A^{+++}}^{\circ}+\lambda_{B^{--}}^{\circ}$$

$$\lambda_{A^{+++}}^{\circ}+3 \lambda_{B^{--}}^{\circ}$$

MHT CET 2023 13th May Evening Shift

MCQ (Single Correct Answer)

-0

What is the molar conductivity of $$0.005 \mathrm{~M} \mathrm{~NaI}$$ solution if it's conductivity is $$6.065 \times 10^{-4} \Omega^{-1} \mathrm{~cm}^{-1} \text { ? }$$

$$121.3 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$$

$$115.1 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$$

$$126.5 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$$

$$131.2 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$$

MHT CET 2023 13th May Evening Shift

MCQ (Single Correct Answer)

-0

Calculate $$E^{\circ}$$ cell for following.

$$\mathrm{Zn}(s)\left|\mathrm{Zn}^{++}(1 \mathrm{M}) \| \mathrm{Pb}^{++}(1 \mathrm{M})\right| \mathrm{Pb}(s)$$ if $$E_{\mathrm{Zn}}^{\circ}=-0.763 \mathrm{~V}$$ and $$E_{\mathrm{Pb}}^{\circ}=-0.126 \mathrm{~V}$$

$$0.637 \mathrm{~V}$$

$$-0.530 \mathrm{~V}$$

$$-0.889 \mathrm{~V}$$

$$0.789 \mathrm{~V}$$

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