MHT CET 2024 15th May Morning Shift | Liquid Solution Question 10 | Chemistry

Calculate Henry's law constant if solubility of gas in water at $25^{\circ} \mathrm{C}$ is $5.14 \times 10^{-4} \mathrm{~mol} \mathrm{dm}^{-3}$ and partial pressure of the gas is 0.75 bar above solution.

$6.85 \times 10^{-4} \mathrm{~mol} \mathrm{dm}^{-3} \mathrm{bar}^{-1}$

$5.14 \times 10^{-4} \mathrm{moldm}^{-3} \mathrm{bar}^{-1}$

$1.028 \times 10^{-4} \mathrm{~mol} \mathrm{dm}^{-3} \mathrm{bar}^{-1}$

$1.371 \times 10^{-4} \mathrm{~mol} \mathrm{dm}^{-3} \mathrm{bar}^{-1}$

MHT CET 2024 15th May Morning Shift

MCQ (Single Correct Answer)

-0

A solution of nonvolatile solute is obtained by dissolving 0.8 g in $0.3 \mathrm{dm}^3$ water has osmotic pressure 0.2 atm at 300 K . Calculate the molar mass of solute.

$$\left[\mathrm{R}=0.082 \mathrm{~atm} \mathrm{dm}^3 \mathrm{~K}^{-1} \mathrm{~mol}^{-1}\right]$$

$300 \mathrm{~g} \mathrm{~mol}^{-1}$

$340 \mathrm{~g} \mathrm{~mol}^{-1}$

$328 \mathrm{~g} \mathrm{~mol}^{-1}$

$352 \mathrm{~g} \mathrm{~mol}^{-1}$

MHT CET 2024 11th May Evening Shift

MCQ (Single Correct Answer)

-0

In a solution, mole fraction of solute is 0.2 , when lowering in vapour pressure is 10 mm Hg . To get lowering of vapour pressure of 20 mm Hg , mole fraction of solute in solution is

0.2

0.4

0.6

0.8

MHT CET 2024 11th May Evening Shift

MCQ (Single Correct Answer)

-0

Which of the following solutions will not show flow of solvent in either direction when separated by semipermeable membrane?

6 g urea $\mathrm{dm}^{-3}$ and 85.5 g sucrose $\mathrm{dm}^{-3}$

15 g urea dm ${ }^{-3}$ and 34.2 g sucrose $\mathrm{dm}^{-3}$

6 g urea dm ${ }^{-3}$ and 34.2 g sucrose $\mathrm{dm}^{-3}$

15 g urea $\mathrm{dm}^{-3}$ and 171 g sucrose $\mathrm{dm}^{-3}$

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