For the following reactions :
(A) CH
3CH
2CH
2Br + KOH $$ \to $$
CH
3CH $$=$$ CH
2 + KBr + H
2O
Which of the following statements is correct?
A
(A) is elimination, (B) and (C) are substitution reactions.
B
(A) is substitution, (B) and (C) are addition reactions.
C
(A) and (B) are elimination reactions and (C) is addition reaction.
D
(A) is elimination, (B) is substitution and (C) is addition reaction.
Explanation
(A) Saturated compound is converted into unsaturated
compound by removal of group of atoms hence, it
is an elimination reaction.
(B) —Br group is replaced by —OH group hence, it is a
substitution reaction.
(C) Addition of Br2 converts an unsaturated compound
into a saturated compound hence, it is an addition
reaction.
