1
MCQ (Single Correct Answer)

AIPMT 2008

How many stereoisomers does this molecule have?

CH3CH$$=$$CHCH2CHBrCH3
A
8
B
2
C
4
D
6

Explanation



Both geometrical isomerism (cis-trans form) and optical isomerism is possible in the given compound.

No. of optical isomer = 2n = 21 = 2
(where n = no. of asymmetric carbon)

Hence total no. of stereoisomers = 2 + 2 = 4
2
MCQ (Single Correct Answer)

AIPMT 2007

If there is no rotation of plane polarised light by a compound in a specific solvent, through to be chiral, it may mean than
A
the compound is certainly meso
B
there is no compound in the solvent
C
the compound may be a racemic mixture
D
the compound is certainly a chiral.

Explanation

Compounds which do not show optical activity inspite of the presence of chiral carbon atoms are called meso-compounds. The absence of optical activity in these compound is due to the presence of a plane of symmetry in their molecules. e.g. meso-tartaric acid is optically inactive.
3
MCQ (Single Correct Answer)

AIPMT 2007

CH3 $$-$$ CHCl $$-$$ CH2 $$-$$ CH3 has a chiral centre. Which one of the following represents its R-configuration?
A
B
C
D

Explanation

4
MCQ (Single Correct Answer)

AIPMT 2006

Which of the following is not chiral?
A
2-Hydroxypropanoic acid
B
2-Butanol
C
2,3-Dibromopentane
D
3-Bromopentane

Explanation



Due to absence of asymmetric carbon atom.

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