Correct relation between dissociation constants of a dibasic acid is
A
Ka1 = Ka2
B
Ka1 > Ka2
C
Ka1 < Ka2
D
Ka1 = $${1 \over {{K_{{a_2}}}}}$$
Explanation
In polyprotic acids the loss of second
proton occurs much less readily than the first.
Usually the Ka values for successive loss of
protons from these acids differ by at least a factor
of 10–3.
$$ \therefore $$ Ka1 > Ka2
3
AIPMT 2001
MCQ (Single Correct Answer)
Ionisation constant of CH3COOH is 1.7 $$ \times $$ 10$$-$$5 and concentration of H+ ions is 3.4 $$ \times $$ 10$$-$$4. Then find out initial concentration of CH3COOH molecules.