1
NEET 2026
MCQ (Single Correct Answer)
+4
-1
Change Language

In a test tube containing a salt, a few drops of dilute $\mathrm{H}_2 \mathrm{SO}_4$ was added, which gave colourless vapours having the smell of vinegar. The vapours turned the blue litmus paper red.

Identify the correct anion from the following :

A

Sulphide, $\mathrm{S}^{2-}$

B

Sulphate, $\mathrm{SO}_4^{2-}$

C

Acetate, $\mathrm{CH}_3 \mathrm{COO}^{-}$

D

Carbonate, $\mathrm{CO}_3^{2-}$

2
NEET 2025
MCQ (Single Correct Answer)
+4
-1
Change Language

Identify the suitable reagent for the following conversion.

NEET 2025 Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 4 English

A
(i) $\mathrm{NaBH}_4$, (ii) $\mathrm{H}^{+} / \mathrm{H}_2 \mathrm{O}$
B
$\quad \mathrm{H}_2 / \mathrm{Pd}-\mathrm{BaSO}_4$
C
(i) $\mathrm{LiAlH}_4$, (ii) $\mathrm{H}^{+} / \mathrm{H}_2 \mathrm{O}$
D
(i) $\mathrm{AlH}(\mathrm{iBu})_2$, (ii) $\mathrm{H}_2 \mathrm{O}$
3
NEET 2025
MCQ (Single Correct Answer)
+4
-1
Change Language

The correct order of decreasing acidity of the following aliphatic acids is

A
$\mathrm{HCOOH}>\mathrm{CH}_3 \mathrm{COOH}>\left(\mathrm{CH}_3\right)_2 \mathrm{CHCOOH}>\left(\mathrm{CH}_3\right)_3 \mathrm{CCOOH}$
B
$\mathrm{HCOOH}>\left(\mathrm{CH}_3\right)_3 \mathrm{CCOOH}>\left(\mathrm{CH}_3\right)_2 \mathrm{CHCOOH}>\mathrm{CH}_3 \mathrm{COOH}$
C
$\left(\mathrm{CH}_3\right)_3 \mathrm{CCOOH}>\left(\mathrm{CH}_3\right)_2 \mathrm{CHCOOH}>\mathrm{CH}_3 \mathrm{COOH}>\mathrm{HCOOH}$
D
$\mathrm{CH}_3 \mathrm{COOH}>\left(\mathrm{CH}_3\right)_2 \mathrm{CHCOOH}>\left(\mathrm{CH}_3\right)_3 \mathrm{CCOOH}>\mathrm{HCOOH}$
4
NEET 2024 (Re-Examination)
MCQ (Single Correct Answer)
+4
-1
Change Language

Select the incorrect reaction among the following :

A
$$ \mathrm{CH}_3 \mathrm{COCl} \xrightarrow[\Delta]{\mathrm{H}_2 \mathrm{O}} \mathrm{CH}_3 \mathrm{COOH} $$
B
NEET 2024 (Re-Examination) Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 6 English Option 2
C
$$ \mathrm{CH}_3 \mathrm{CH}_2 \mathrm{OH} \xrightarrow[\text { (i) } \mathrm{H}_3 \mathrm{O}^{\oplus}]{\text { (i) } \mathrm{KMOO}_4 / \mathrm{OH}^{-}} \mathrm{CH}_3 \mathrm{COOH} $$
D
$$ \mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{OH} \xrightarrow{\mathrm{CrO}_3-\mathrm{H}_2 \mathrm{SO}_4} \mathrm{CH}_3 \mathrm{CH}_2 \mathrm{COOH} $$

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