In this reaction :
CH3CHO + HCN $$ \to $$ CH3CH(OH)CN
$$\buildrel {HOH} \over
\longrightarrow $$ CH3CH(OH)COOH
an asymmetric centre is generated. The acid obtained would be
A
$$D$$-isomer
B
$$L$$-isomer
C
50% $$D$$ + 50% $$L$$-isomer
D
20% $$D$$ + 80% $$L$$-isomer
Explanation
3
AIPMT 2002
MCQ (Single Correct Answer)
are
A
resonating structures
B
tautomers
C
geometrical isomers
D
optical isomers.
Explanation
They are resonating forms because the
position of the atomic nuclei remain the same and
only electron redistribution has occurred.
4
AIPMT 2002
MCQ (Single Correct Answer)
In the following reaction product $$P$$ is
A
RCH2OH
B
RCOOH
C
RCHO
D
RCH3
Explanation
Questions Asked from Aldehydes, Ketones and Carboxylic Acids
On those following papers in MCQ (Single Correct Answer)
Number in Brackets after Paper Indicates No. of Questions
