1
NEET 2019
MCQ (Single Correct Answer)
+4
-1
pH of a saturated solution of Ca(OH)2 is 9. The solubility product (Ksp) of Ca(OH)2 is :
A
0.125 × 10–15
B
0.5 × 10–10
C
0.5 × 10–15
D
0.25 × 10–10
2
NEET 2019
MCQ (Single Correct Answer)
+4
-1
Which will make basic buffer?
A
100 mL of 0.1 M HCl + 200 mL of 0.1 M NH4OH
B
100 mL of 0.1 M HCl + 100 mL of 0.1 M NHOH
C
50 mL of 0.1 M NaOH + 25 mL of 0.1 M CH3COOH
D
100 mL of 0.1 M CH3COOH + 100 mL of 0.1 M NaOH
3
NEET 2018
MCQ (Single Correct Answer)
+4
-1
Following solutions were prepared by mixing different volumes of NaOH and HCl of different concentrations :

A. 60 mL $${M \over {10}}$$ HCl + 40 mL $${M \over {10}}$$ NaOH

B. 55 mL $${M \over {10}}$$ HCl + 45 mL $${M \over {10}}$$ NaOH

C. 75 mL $${M \over {5}}$$ HCl + 25 mL $${M \over {5}}$$ NaOH

D. 100 mL $${M \over {10}}$$ HCl + 100 mL $${M \over {10}}$$ NaOH

pH of which one of them will be equal to 1?
A
B
B
A
C
D
D
C
4
NEET 2018
MCQ (Single Correct Answer)
+4
-1
The solubility of BaSO4 in water is 2.42 × 10–3 g L–1 at 298 K. The value of its solubility product (Ksp) will be (Given molar mass of BaSO4 = 233 g mol–1)
A
1.08 × 10–10 mol2 L–2
B
1.08 × 10–12 mol2 L–2
C
1.08 × 10–14 mol2 L–2
D
1.08 × 10–8 mol2 L–2
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