AIPMT 2009 | Rotational Motion Question 58 | Physics

AIPMT 2009

MCQ (Single Correct Answer)

-1

If $$\overrightarrow F $$ is the force acting on a particle having position vector $$\overrightarrow r $$ and $$\overrightarrow \tau $$ be the torque of this force about the origin, then

$$\overrightarrow r .\overrightarrow \tau > 0$$ and $$\overrightarrow F .\overrightarrow \tau < 0$$

$$\overrightarrow r .\overrightarrow \tau = 0$$ and $$\overrightarrow F .\overrightarrow \tau = 0$$

$$\overrightarrow r .\overrightarrow \tau = 0$$ and $$\overrightarrow F .\overrightarrow \tau \ne 0$$

$$\vec r.\vec \tau \ne 0$$ and $$\overrightarrow F .\overrightarrow \tau = 0$$

AIPMT 2009

MCQ (Single Correct Answer)

-1

Four identical thin rods each of mass M and length $$l$$, form a square frame. Moment of inertia of this frame about an axis through the centre of the square and perpendicular to its plane is

$${2 \over 3}M{l^2}$$

$${{13} \over 3}M{l^2}$$

$${1 \over 3}M{l^2}$$

$${4 \over 3}M{l^2}$$

AIPMT 2009

MCQ (Single Correct Answer)

-1

A thin circular ring of mass M and radius R is rotating in a horizontal plane about an axis vertical to its plane with a constant angular velocity $$\omega $$. If two objects each of mass m be attached gently to the opposite ends of a diameter of the ring, the ring will then rotate with an angular velocity

$${{\omega M} \over {M + 2m}}$$

$${{\omega \left( {M + 2m} \right)} \over M}$$

$${{\omega M} \over {M + m}}$$

$${{\omega \left( {M - 2m} \right)} \over {M + 2m}}$$

AIPMT 2008

MCQ (Single Correct Answer)

-1

The ratio of the radii of gyration of a circular disc to that of a circular ring, each of same mass and radius, around their respective axes is

$$\sqrt 2 :1$$

$$\sqrt 2 :\sqrt 3 $$

$$\sqrt 3 :\sqrt 2 $$

$$1:\sqrt 2 $$

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