1
NEET 2016 Phase 1
MCQ (Single Correct Answer)
+4
-1
Change Language
Given the value of Rydberg constant is 107 m$$-$$1, the wave number of the last line of the Balmer series in hydrogen spectrum will be
A
0.25 $$ \times $$ 107 m$$-$$1
B
2.5 $$ \times $$ 107 m$$-$$1
C
0.025 $$ \times $$ 104 m$$-$$1
D
0.5 $$ \times $$ 107 m$$-$$1
2
AIPMT 2015
MCQ (Single Correct Answer)
+4
-1
Change Language
In the spectrum of hydrogen, the ratio of the longest wavelength in the Lyman series to the longest wavelength in the Balmer series is
A
$${{27} \over 5}$$
B
$${5 \over {27}}$$
C
$${4 \over 9}$$
D
$${9 \over 4}$$
3
AIPMT 2015
MCQ (Single Correct Answer)
+4
-1
Change Language
A nucleus of uranium decays at rest into nuclei of thorium and helium. Then
A
The helium nucleus has more momentum than the thorium nucleus.
B
The helium nucleus has less kinetic energy than the thorium nucleus.
C
The helium nucleus has more kinetic energy than the thorium nucleus.
D
The helium nucleus has less momentum than the thorium nucleus.
4
AIPMT 2015 Cancelled Paper
MCQ (Single Correct Answer)
+4
-1
Change Language
Consider 3rd orbit of He+ (Helium), using non-relativistic approach, the speed of electron in this orbit will be [given K = 9 $$ \times $$ 109 constant, Z = 2 and h (Planck's Constant) = 6.6 $$ \times $$ 10$$-$$34 J s]
A
0.73 $$ \times $$ 106 m/s
B
3.0 $$ \times $$ 108 m/s
C
2.92 $$ \times $$ 106 m/s
D
1.46 $$ \times $$ 106 m/s
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