1
AIPMT 2010 Prelims
MCQ (Single Correct Answer)
+4
-1
An alpha nucleus of energy $${1 \over 2}$$ mv2 bombards a heavy nuclear target of charge Ze. Then the distance of closest approach for the alpha nucleus will be proportional to
A
$${1 \over {Ze}}$$
B
v2
C
$${1 \over m}$$
D
$${1 \over {{v_4}}}$$
2
AIPMT 2009
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
In the nuclear decay given below

$${}_Z^AX \to {}_{Z + 1}^AY \to {}_{Z - 1}^{A - 4}B{}^ * \to {}_{Z - 1}^{A - 4}B,$$

the particles emitted in the sequence are
A
$$\gamma $$, $$\beta $$, $$\alpha $$
B
$$\beta $$, $$\gamma $$, $$\alpha $$
C
$$\alpha $$, $$\beta $$, $$\gamma $$
D
$$\beta $$, $$\alpha $$, $$\gamma $$
3
AIPMT 2009
MCQ (Single Correct Answer)
+4
-1
In a Rutherford scattering experiment when a projectile of charge z1 and mass M1 approaches a target nucleus of charge z2 and mass M2, the distance of closest approach is r0. The energy of the projectile is
A
directly proportional to z1z2
B
inversely proportional to z1
C
directly proportional to mass M1
D
directly proportional to M1 $$ \times $$ M2
4
AIPMT 2009
MCQ (Single Correct Answer)
+4
-1
The ionization energy of the electron in the hydrogen atom in its ground state is 13.6 eV. The atoms are excited to higher energy levels to emit radiations of 6 wavelengths, Maximum wavelength of emitted radiation corresponds to the transition between
A
n = 3 to n = 1 states
B
n = 2 to n = 1 states
C
n = 4 to n = 3 states
D
n = 3 to n = 2 states
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