1
NEET 2019
MCQ (Single Correct Answer)
+4
-1
At a point A on the earth’s surface the angle of dip, $$\delta $$ = + 25o. At a point B on the earth's surface the angle of dip, $$\delta $$ = – 25o. We can interpret that :
A
A is located in the southern hemisphere and B is located in the northern hemisphere.
B
A is located in the northern hemisphere and B is located in the southern hemisphere.
C
A and B are both located in the southern hemisphere.
D
A and B are both located in the northerm hemisphere.
2
NEET 2018
MCQ (Single Correct Answer)
+4
-1
A thin diamagnetic rod is placed vertically between the poles of an electromagnet. When the current in the electromagnet is switched on, then the diamagnetic rod is pushed up, out of the horizontal magnetic field. Hence the rod gains gravitational potential energy. The work required to do this comes from
A
The current source
B
The magnetic field
C
The lattice structure of the material of the rod
D
The induced electric field due to the changing magnetic field
3
NEET 2017
MCQ (Single Correct Answer)
+4
-1
If $$\theta $$1 and $$\theta $$2 be the apparent angles of dip observed in two vertical planes at right angles to each other, then the true angle of dip $$\theta $$ is given by
A
tan2$$\theta $$ = tan2$$\theta $$1 + tan2$$\theta $$2
B
cot2$$\theta $$ = cot2$$\theta $$1 $$-$$cot2$$\theta $$2
C
tan2$$\theta $$ = tan2$$\theta $$1 $$-$$ tan2$$\theta $$2
D
cot2$$\theta $$ = cot2$$\theta $$1 + cot2$$\theta $$2
4
NEET 2017
MCQ (Single Correct Answer)
+4
-1
A 250-turn rectangular coil of length 2.1 cm and width 1.25 cm carries a current of 85 $$\mu $$A and subjected to a magnetic field of strength 0.85 T. Work done for rotating the coil by 180o against the torque is
A
4.55 $$\mu $$J
B
2.3 $$\mu $$J
C
1.15 $$\mu $$J
D
9.1 $$\mu $$J
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