AIPMT 2002 | Waves Question 53 | Physics

AIPMT 2002

MCQ (Single Correct Answer)

-1

A wave travelling in positive X-direction with a $$=$$ 0.2 ms^$$-$$2, velocity = 360 ms^$$-$$1 and $$\lambda $$ $$=$$ 60 m, then correct expression for the wave is

$$y = 0.2\sin \left[ {2\pi \left( {6t + {x \over {60}}} \right)} \right]$$

$$y = 0.2\sin \left[ {\pi \left( {6t + {x \over {60}}} \right)} \right]$$

$$y = 0.2\sin \left[ {2\pi \left( {6t - {x \over {60}}} \right)} \right]$$

$$y = 0.2\sin \left[ {\pi \left( {6t - {x \over {60}}} \right)} \right]$$

AIPMT 2001

MCQ (Single Correct Answer)

-1

Two waves having equation x₁ = $$a$$sin($$\omega $$t $$-$$ kx + $$\phi $$₁), x₂ = asin($$\omega $$t $$-$$kx + $$\phi $$₂). If in the resultant wave the frequency and amplitude remain equal to amplitude of superimposing waves, the phase difference between them is

$${\pi \over 6}$$

$${{2\pi } \over 3}$$

$${\pi \over 4}$$

$${\pi \over 3}$$

AIPMT 2001

MCQ (Single Correct Answer)

-1

The equation of a wave is represented by

y $$=$$ 10^$$-$$4 sin(100t $$-$$ $${x \over {10}}$$) m. then the velocity of wave will be

100 m/s

4 m/s

1000 m/s

10 m/s

AIPMT 2001

MCQ (Single Correct Answer)

-1

If the tension and diameter of a sonometer wire of fundamental frequency n is doubled and density is halved then its fundamental frequency will become

$${\pi \over 4}$$

$$\sqrt 2 n$$

$${n \over {\sqrt 2 }}$$

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