1
AIPMT 2002
+4
-1
A wave travelling in positive X-direction with a $$=$$ 0.2 ms$$-$$2, velocity = 360 ms$$-$$1 and $$\lambda$$ $$=$$ 60 m, then correct expression for the wave is
A
$$y = 0.2\sin \left[ {2\pi \left( {6t + {x \over {60}}} \right)} \right]$$
B
$$y = 0.2\sin \left[ {\pi \left( {6t + {x \over {60}}} \right)} \right]$$
C
$$y = 0.2\sin \left[ {2\pi \left( {6t - {x \over {60}}} \right)} \right]$$
D
$$y = 0.2\sin \left[ {\pi \left( {6t - {x \over {60}}} \right)} \right]$$
2
AIPMT 2001
+4
-1
Two waves having equation x1 = $$a$$sin($$\omega$$t $$-$$ kx + $$\phi$$1), x2 = asin($$\omega$$t $$-$$kx + $$\phi$$2). If in the resultant wave the frequency and amplitude remain equal to amplitude of superimposing waves, the phase difference between them is
A
$${\pi \over 6}$$
B
$${{2\pi } \over 3}$$
C
$${\pi \over 4}$$
D
$${\pi \over 3}$$
3
AIPMT 2001
+4
-1
The equation of a wave is represented by

y $$=$$ 10$$-$$4 sin(100t $$-$$ $${x \over {10}}$$) m. then the velocity of wave will be
A
100 m/s
B
4 m/s
C
1000 m/s
D
10 m/s
4
AIPMT 2001
+4
-1
If the tension and diameter of a sonometer wire of fundamental frequency n is doubled and density is halved then its fundamental frequency will become
A
$${\pi \over 4}$$
B
$$\sqrt 2 n$$
C
n
D
$${n \over {\sqrt 2 }}$$
EXAM MAP
Medical
NEET