NEET 2017 | Oscillations Question 17 | Physics

NEET 2017

MCQ (Single Correct Answer)

-1

A spring of force constant k is cut into lengths of ratio 1 : 2 : 3. They are connected in series and the new force constant is K'. Then they are connected in parallel and force constant is k''. Then k' : k'' is

1 : 9

1 : 11

1 : 14

1 : 6

NEET 2017

MCQ (Single Correct Answer)

-1

A particle executes linear simple harmonic motion with an amplitude of 3 cm. When the particle is at 2 cm from the mean position, the magnitude of its velocity is equal to that of its acceleration. Then its time period in second is

$${{\sqrt 5 } \over {2\pi }}$$

$${{4\pi } \over {\sqrt 5 }}$$

$${{2\pi } \over {\sqrt 3 }}$$

$${{\sqrt 5 } \over \pi }$$

NEET 2016 Phase 2

MCQ (Single Correct Answer)

-1

A body of mass m is attached to the lower end of a spring whose upper end is fixed. The spring has negligible mass. When the mass m is slightly pulled down and released, it oscillates with a time period of 3s. When the mass m is increased by 1 kg, the time period of oscillations becomes 5 s. The value of m in kg is

$${3 \over 4}$$

$${4 \over 3}$$

$${{16} \over 9}$$

$${9 \over {16}}$$

AIPMT 2015

MCQ (Single Correct Answer)

-1

A particle is executing a simple harmonic motion. Its maximum acceleration is $$\alpha $$ and maximum velocity is $$\beta $$. Them, its time period of vibration will be

$${{{\beta ^2}} \over \alpha }$$

$${{2\pi \beta } \over \alpha }$$

$${{{\beta ^2}} \over {{\alpha ^2}}}$$

$${\alpha \over \beta }$$

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