NEET 2013 (Karnataka) | Gravitation Question 32 | Physics

NEET 2013 (Karnataka)

MCQ (Single Correct Answer)

-1

A particle of mass 'm' is kept at rest at a height 3R from the surface of earth, where 'R' is radius of earth and 'M' is mass of earth. The minimum speed with which it should be projected , so that it does not return back, is
(g is acceleration due to gravity on the surface of earth)

$${\left( {{{GM} \over {2R}}} \right)^{1/2}}$$

$${\left( {{{gR} \over 4}} \right)^{1/2}}$$

$${\left( {{{2g} \over R}} \right)^{1/2}}$$

$${\left( {{{GM} \over R}} \right)^{1/2}}$$

NEET 2013

MCQ (Single Correct Answer)

-1

A body of mass 'm' is taken from the earth's surface to the height equal to twice the radius (R) of the earth. The change in potential energy of body will be

3mgR

$${1 \over 3}$$mgR

mg2R

$${2 \over 3}$$ mgR

NEET 2013

MCQ (Single Correct Answer)

-1

Infinite number of bodies, each of mass 2 kg are situated on x-axis at distance 1 m, 2 m, 4 m, 8 m, . . . , respectively, from the origin. The resulting gravitational potential due to this system at the origin will be

$$ - {4 \over 3}$$ G

$$-$$ 4G

$$-$$ G

$$ - {8 \over 3}$$ G

AIPMT 2012 Mains

MCQ (Single Correct Answer)

-1

If $${v_e}$$ is escape velocity and $${v_o}$$ is orbital velocity of a satellite for orbit close to the earth's surface, then these are related by

$${v_o} = \sqrt {2{v_e}} $$

v_o $$=$$ v_e

$${v_e} = \sqrt {2{v_o}} $$

$${v_e} = \sqrt 2 {v_o}$$

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