AIPMT 2010 Prelims | Rotational Motion Question 49 | Physics

AIPMT 2010 Prelims

MCQ (Single Correct Answer)

-1

A circular disk of moment of inertia $${I_t}$$ is rotating in a horizontal plane, about its symmetry axis, with a constant angular speed $${\omega _i}$$. Another disk of moment of inertia $${I_b}$$ is dropped coaxially onto the rotating disk. Initially the second disk has zero angular speed. Eventually both the disks rotate with a constant angular speed $$\omega $$. The energy lost by the initially rotating disc to friction is

$${1 \over 2}{{I_b^2} \over {\left( {{I_t} + {I_b}} \right)}}\omega _i^2$$

$${1 \over 2}{{I_t^2} \over {\left( {{I_t} + {I_b}} \right)}}\omega _i^2$$

$${{{I_b} - {I_t}} \over {\left( {{I_t} + {I_b}} \right)}}\omega _i^2$$

$${1 \over 2}{{{I_b}{I_t}} \over {\left( {{I_t} + {I_b}} \right)}}\omega _i^2$$

AIPMT 2010 Prelims

MCQ (Single Correct Answer)

-1

A gramophone record is revolving with an angular velocity $$\omega $$. A coin is placed at a distance r from the centre of the record. The static coefficient of friction is $$\mu $$. The coin will revolve with the record if

r = $$\mu $$g$$\omega $$²

r < $${{{\omega ^2}} \over {\mu g}}$$

$$r \le {{\mu g} \over {{\omega ^2}}}$$

$$r \ge {{\mu g} \over {{\omega ^2}}}$$

AIPMT 2009

MCQ (Single Correct Answer)

-1

A thin circular ring of mass M and radius R is rotating in a horizontal plane about an axis vertical to its plane with a constant angular velocity $$\omega $$. If two objects each of mass m be attached gently to the opposite ends of a diameter of the ring, the ring will then rotate with an angular velocity

$${{\omega M} \over {M + 2m}}$$

$${{\omega \left( {M + 2m} \right)} \over M}$$

$${{\omega M} \over {M + m}}$$

$${{\omega \left( {M - 2m} \right)} \over {M + 2m}}$$

AIPMT 2009

MCQ (Single Correct Answer)

-1

Four identical thin rods each of mass M and length $$l$$, form a square frame. Moment of inertia of this frame about an axis through the centre of the square and perpendicular to its plane is

$${2 \over 3}M{l^2}$$

$${{13} \over 3}M{l^2}$$

$${1 \over 3}M{l^2}$$

$${4 \over 3}M{l^2}$$

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