MHT CET 2021 24th September Evening Shift | Ionic Equilibrium Question 80 | Chemistry

The solubility of sparingly soluble salt $$\mathrm{AB}_2$$ is $$1.0 \times 10^{-4} \mathrm{~mol} \mathrm{~dm}^{-3}$$. What is it's solubility product?

$$2 \times 10^{-12}$$

$$4 \times 10^{-8}$$

$$4 \times 10^{-12}$$

$$2 \times 10^{-8}$$

MHT CET 2021 24th September Evening Shift

MCQ (Single Correct Answer)

-0

What is the $$\mathrm{pH}$$ of $$0.005 \mathrm{~M} \mathrm{~H}_2 \mathrm{SO}_4$$ solution?

5.0

2.3

3.3

2.0

MHT CET 2021 24th September Evening Shift

MCQ (Single Correct Answer)

-0

The solubility product expression for $$\mathrm{Ca}_3\left(\mathrm{PO}_4\right)_2$$ is represented as

$$\mathrm{K}_{\mathrm{sp}}=\left[\mathrm{Ca}^{2+}\right]^2\left[\mathrm{PO}_4{ }^3\right]^2$$

$$\mathrm{K}_{\mathrm{sp}}=\left[\mathrm{Ca}^{2+}\right]^3\left[\mathrm{PO}_4{ }^3\right]^2$$

$$\mathrm{K}_{\mathrm{sp}}=\left[\mathrm{Ca}^{2+}\right]\left[\mathrm{PO}_4{ }^2\right]^3$$

$$\mathrm{K}_{\mathrm{sp}}=\left[\mathrm{Ca}^{2+}\right]\left[\mathrm{PO}_4{ }^2\right]$$

MHT CET 2021 24th September Morning Shift

MCQ (Single Correct Answer)

-0

Identify conjugate acid-base pair in the following reaction.

$$ \mathrm{HCl}_{(\mathrm{aq})}+\mathrm{H}_2 \mathrm{O}_{(l)} \rightleftharpoons \mathrm{H}_3 \mathrm{O}_{(\mathrm{aq})}^{+}+\mathrm{Cl}_{(\mathrm{aq})}^{-}$$

$$ \mathrm{H}_3 \mathrm{O}_{(\mathrm{aq})}^{+} \text {and } \mathrm{Cl}_{(\mathrm{aq})}^{-} $$

$$ \mathrm{H}_3 \mathrm{O}_{(\mathrm{aq})}^{+} \text {and } \mathrm{H}_2 \mathrm{O}_{(l)} $$

$$ \mathrm{HCl}_{(\mathrm{aq})} \text { and } \mathrm{H}_2 \mathrm{O}_{(l)} $$

$$ \mathrm{Cl}_{(\mathrm{aq})}^{-} \text {and } \mathrm{H}_2 \mathrm{O}_{(l)} $$

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