1
COMEDK 2026 Morning Shift
MCQ (Single Correct Answer)
+1
-0

The product of three numbers in geometric progression is 8 and the sum of the product of the numbers taken in pairs is 14 . Find the numbers.

A

$$ 4,2,1 \text { and } 1,2,4 $$

B

$\frac{1}{4}, \frac{1}{2}, 1$ and $1, \frac{1}{2}, \frac{1}{4}$

C

$4 \sqrt{2}, \sqrt{2}, 1$ and $1, \sqrt{2}, 4 \sqrt{2}$

D

$-4,-2,1$ and $1,-2,-4$

2
COMEDK 2026 Morning Shift
MCQ (Single Correct Answer)
+1
-0

Let ' $\boldsymbol{a}$ ' and ' $\mathbf{b}$ ' be two numbers where $\boldsymbol{a}<\boldsymbol{b}$. The geometric mean of these numbers exceeds the smaller number by 12 and the arithmetic mean is smaller than the larger number by 24 . Then the value of $|\boldsymbol{b}-\boldsymbol{a}|$ is:

A

52

B

44

C

48

D

60

3
COMEDK 2025 Evening Shift
MCQ (Single Correct Answer)
+1
-0
A geometric progression consists of an even number of terms. If the sum of all the terms is five times the sum of the terms occupying the odd places, then the common ratio of the geometric progression is
A
$r=4$
B
$r=3$
C
$r=6$
D
$r=2$
4
COMEDK 2025 Evening Shift
MCQ (Single Correct Answer)
+1
-0
Given that n number of arithmetic means are inserted between two pairs of numbers $a, 2 b$ and $2 a, b$; where $a, b \in R$. If the $m^{\text {th }}$ means in the two cases are the same, then the ratio $a: b$ is equal to
A
$m:(n-m+1)$
B
$n:(n-m+1)$
C
$(n-m+1): m$
D
$(n-m+1): n$

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