COMEDK 2024 Evening Shift | Sequences and Series Question 1 | Mathematics

Consider an infinite geometric series with first term '$$a$$' and common ratio '$$r$$'. If the sum of infinite geometric series is 4 and the second term is $$\frac{3}{4}$$ then

$$ a=1 \quad r=-\frac{3}{4} $$

$$ a=3 \quad r=\frac{1}{4} $$

$$ a=-3 \quad r=-\frac{1}{4} $$

$$ a=-1 \quad r=\frac{3}{4} $$

COMEDK 2024 Evening Shift

MCQ (Single Correct Answer)

-0

If two positive numbers are in the ratio $$3+2 \sqrt{2}: 3-2 \sqrt{2}$$, then the ratio between their A.M (arithmetic mean) and G.M (geometric mean) is

$$3: 4$$

$$6: 1$$

$$3: 2$$

$$3: 1$$

COMEDK 2024 Evening Shift

MCQ (Single Correct Answer)

-0

A number consists of three digits in geometric progression. The sum of the right hand and left hand digits exceeds twice the middle digit by 1 and the sum of left hand and middle digits is two third of the sum of the middle and right hand digits. Then the sum of digits of number is

$$\frac{1}{4}$$

469

109

COMEDK 2024 Afternoon Shift

MCQ (Single Correct Answer)

-0

The sum of first three terms of a geometric progression is 16 and the sum of next three terms is 128 . The sum to $$\mathrm{n}$$ terms of the geometric progression is

$$ \frac{8}{3}\left(3^n-1\right) $$

$$ \frac{16}{7}\left(2^n-1\right) $$

$$ \frac{16}{7}\left(3^n-1\right) $$

$$ \frac{8}{3}\left(2^n-1\right) $$

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