MHT CET 2025 23rd April Morning Shift | Ionic Equilibrium Question 20 | Chemistry

Solubility of binary sparingly soluble salt is $1.12 \times 10^{-4} \mathrm{~g} / \mathrm{dm}^3$. Calculate its solubility product (molar mass of salt $=112 \mathrm{~g} \mathrm{~mol}^{-1}$ )

$1 \times 10^{-3}$

$1 \times 10^{-6}$

$1 \times 10^{-9}$

$1 \times 10^{-12}$

MHT CET 2025 22nd April Evening Shift

MCQ (Single Correct Answer)

-0

Identify conjugate acid-base pair from following equilibrium reaction.

$$ \mathrm{HSO}_{3(\mathrm{aq})}^{-}+\mathrm{H}_3 \mathrm{O}_{(\mathrm{aq})}^{+} \rightleftharpoons \mathrm{H}_2 \mathrm{SO}_3+\mathrm{H}_2 \mathrm{O} $$

$\quad \mathrm{H}_2 \mathrm{SO}_3$ and $\mathrm{HSO}_3^{-}$

$\mathrm{HSO}_3^{-}$and $\mathrm{H}_3 \mathrm{O}^{+}$

$\mathrm{H}_2 \mathrm{SO}_3$ and $\mathrm{H}_2 \mathrm{O}$

$\mathrm{H}_3 \mathrm{O}^{+}$and $\mathrm{H}_2 \mathrm{SO}_3$

MHT CET 2025 22nd April Evening Shift

MCQ (Single Correct Answer)

-0

A weak monoacidic base dissociates to $1.5 \%$ in 0.001 M solution at 298 K . Calculate the dissociation constant of weak base.

$2.25 \times 10^{-7}$

$3.05 \times 10^{-7}$

$2.5 \times 10^{-5}$

$3.725 \times 10^{-6}$

MHT CET 2025 22nd April Evening Shift

MCQ (Single Correct Answer)

-0

The solubility product of NiS is $4.9 \times 10^{-5}$ at 298 K . Calculate its solubility in $\mathrm{mol} \mathrm{dm}^{-3}$ at the same temperature?

$1.69 \times 10^{-3}$

$7.0 \times 10^{-3}$

$2.45 \times 10^{-3}$

$6.18 \times 10^{-3}$

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Some Basic Concepts of Chemistry Atomic Structure States of Matter Thermodynamics Chemical Equilibrium Ionic Equilibrium Liquid Solution Redox Reactions Surface Chemistry Solid State Electrochemistry Chemical Kinetics Nuclear Chemistry

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