MHT CET 2023 12th May Morning Shift | Chemical Kinetics Question 109 | Chemistry

Identify rate law expression for $$2 \mathrm{NO}_{(\mathrm{g})}+\mathrm{Cl}_{2(\mathrm{~g})} \rightarrow 2 \mathrm{NOCl}_{(\mathrm{g})}$$ if the reaction is second order in $$\mathrm{NO}$$ and first order in $$\mathrm{Cl}_2$$.

Rate $$=\mathrm{k}[\mathrm{NO}]^2\left[\mathrm{Cl}_2\right]$$

Rate $$=\mathrm{k}[\mathrm{NO}]\left[\mathrm{Cl}_2\right]$$

$$\mathrm{Rate}=\mathrm{k}[\mathrm{NO}]^2$$

Rate $$=\mathrm{k}\left[\mathrm{Cl}_2\right]$$

MHT CET 2023 11th May Evening Shift

MCQ (Single Correct Answer)

-0

For a reaction $$\mathrm{A}+\mathrm{B} \rightarrow$$ product, if $$[\mathrm{A}]$$ is doubled keeping $$[\mathrm{B}]$$ constant, the rate of reaction doubles. Calculate the order of reaction with respect to A.

1/2

MHT CET 2023 11th May Evening Shift

MCQ (Single Correct Answer)

-0

Calculate the rate constant of the first order reaction if $$80 \%$$ of the reactant reacted in 15 minute.

0.11 minute$$^{-1}$$

0.22 minute$$^{-1}$$

0.34 minute$$^{-1}$$

0.42 minute$$^{-1}$$

MHT CET 2023 11th May Evening Shift

MCQ (Single Correct Answer)

-0

Identify the expression for average rate for following reaction.

$$\mathrm{N}_{2(\mathrm{~g})}+3 \mathrm{H}_{2(\mathrm{~g})} \rightarrow 2 \mathrm{NH}_{3(\mathrm{~g})}$$

$$\frac{-\Delta\left[\mathrm{N}_2\right]}{\Delta \mathrm{t}}=-\frac{1}{3} \frac{\Delta\left[\mathrm{H}_2\right]}{\Delta \mathrm{t}}=\frac{1}{2} \frac{\Delta\left[\mathrm{NH}_3\right]}{\Delta \mathrm{t}}$$

$$-\frac{1}{3} \frac{\Delta\left[\mathrm{N}_2\right]}{\Delta \mathrm{t}}=\frac{\Delta\left[\mathrm{H}_2\right]}{\Delta \mathrm{t}}=\frac{1}{2} \frac{\Delta\left[\mathrm{NH}_3\right]}{\Delta \mathrm{t}}$$

$$\frac{-\Delta\left[\mathrm{N}_2\right]}{\Delta \mathrm{t}}=\frac{-\Delta\left[\mathrm{H}_2\right]}{\Delta \mathrm{t}}=\frac{\Delta\left[\mathrm{NH}_3\right]}{\Delta \mathrm{t}}$$

$$-\frac{1}{2} \frac{\Delta\left[\mathrm{N}_2\right]}{\Delta \mathrm{t}}=\frac{-\Delta\left[\mathrm{H}_2\right]}{\Delta \mathrm{t}}=\frac{1}{3} \frac{\Delta\left[\mathrm{NH}_3\right]}{\Delta \mathrm{t}}$$

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