1
COMEDK 2024 Afternoon Shift
MCQ (Single Correct Answer)
+1
-0

$$ \text { The general solution of } \frac{d y}{d x}=\sin ^{-1} x \text { is } $$

A
$$ y=x \sin ^{-1} x+\sqrt{1-x^2}+C $$
B
$$ y=x \sin ^{-1} x-\sqrt{1-x^2}+C $$
C
$$ y=-x \sin ^{-1} x+\sqrt{1-x^2}+C $$
D
$$ y=-x \sin ^{-1} x-\sqrt{1-x^2}+C $$
2
COMEDK 2024 Afternoon Shift
MCQ (Single Correct Answer)
+1
-0

Degree of the differential equation $$\log \left(\frac{d y}{d x}\right)^{\frac{1}{2}}=5 x+4 y$$ is

A
Not defined
B
4
C
1
D
2
3
COMEDK 2024 Morning Shift
MCQ (Single Correct Answer)
+1
-0

The particular solution of $$\frac{d y}{d x}+\sqrt{\frac{1-y^2}{1-x^2}}=0$$, when $$x=0, y=\frac{1}{2}$$ is

A
$$\sin ^{-1} x+\sin ^{-1} y=\frac{\pi}{6}$$
B
$$\sin ^{-1} x+\sin ^{-1} y=\frac{\pi}{2}$$
C
$$\sin ^{-1} x-\sin ^{-1} y=\frac{\pi}{2}$$
D
$$\sin ^{-1} x+\sin ^{-1} y=\frac{\pi}{3}$$
4
COMEDK 2024 Morning Shift
MCQ (Single Correct Answer)
+1
-0

The particular solution of the differential equation $$\cos x \frac{d y}{d x}+y=\sin x$$ at $$y(0)=1$$

A
$$y(\sec x+\tan x)=\sec x+\tan x-x+1$$
B
$$y(\sec x+\tan x)=\sec x+\tan x-x$$
C
$$y(\sec x+\tan x)=\sec x+\tan x+x$$
D
$$y(\sec x+\tan x)=\sec x+\tan x-x+2$$
COMEDK Subjects
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