1
COMEDK 2023 Evening Shift
MCQ (Single Correct Answer)
+1
-0

The particular solution of $$e^{\frac{d y}{d x}}=2 x+1$$ given that $$y=1$$ when $$x=0$$ is

A
$$ y=\left(x+\frac{1}{2}\right) \log |2 x+1|-x+1 $$
B
$$ y=(x+1) \log |2 x+1|-x+1 $$
C
$$ y=\left(x+\frac{1}{2}\right) \log |2 x+1|-\frac{1}{2} x+1 $$
D
$$ y=\left(x-\frac{1}{2}\right) \log |2 x+1|-x-1 $$
2
COMEDK 2023 Evening Shift
MCQ (Single Correct Answer)
+1
-0

The general solution of the differential equation $$\left(1+y^2\right) d x=\left(\tan ^{-1} y-x\right) d y$$

A
$$ x=\tan ^{-1} y-1+c e^{\tan ^{-1} y} $$
B
$$ x=\tan ^{-1} y-1+c e^{-\tan ^{-1} y} $$
C
$$ x=\tan ^{-1} y+c e^{\tan ^{-1} y} $$
D
$$ x=c \tan ^{-1} y+e^{-\tan ^{-1} y} $$
3
COMEDK 2023 Evening Shift
MCQ (Single Correct Answer)
+1
-0

The solution of the differential equation $$\frac{d y}{d x}+y \cos x=\frac{1}{2} \sin 2 x$$

A
$$ y e^{\sin x}=e^{\sin x}(\sin x+1)+c $$
B
$$ y e^{\sin x}=e^{\sin x}(\sin x-1)+c $$
C
$$ y e^{\sin 2 x}=e^{\sin 2 x}(\sin x-1)+c $$
D
$$ y e^{\cos x}=e^{\sin x}(\cos x-1)+c $$
4
COMEDK 2023 Evening Shift
MCQ (Single Correct Answer)
+1
-0

The sum of the degree and order of the following differential equation $$\left[1-\left(\frac{d y}{d x}\right)^2\right]^{\frac{3}{2}}=k x \frac{d^2 y}{d x^2}$$

A
$$\frac{5}{2}$$
B
4
C
$$\frac{3}{2}$$
D
3
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