MHT CET 2025 19th April Morning Shift | Chemical Kinetics Question 35 | Chemistry

In a first order reaction concentration of reactant decreases from 20 milli $\mathrm{mol} \mathrm{dm}^{-3}$ to 8 milli $\mathrm{mol} \mathrm{dm}^{-}$ in 40 minutes, find rate constant of reaction?

0.011 minute ${ }^{-1}$

0.023 minute ${ }^{-1}$

0.032 minute ${ }^{-1}$

0.041 minute ${ }^{-1}$

MHT CET 2025 19th April Morning Shift

MCQ (Single Correct Answer)

-0

Which from following is correct regarding $t_{1 / 2}$ of reaction if we double the initial concentration of a reactant in first order reaction?

$\mathrm{t}_{1 / 2}$ will increase by two times

$t_{1 / 2}$ will decrease by four times

$t_{1 / 2}$ remains the same

$\mathrm{t}_{1 / 2}$ will decrease by two times

MHT CET 2024 16th May Evening Shift

MCQ (Single Correct Answer)

-0

In a first order reaction $60 \%$ of the reactant converts into product in 45 minute. Calculate rate constant of the reaction.

0.0102 minute $^{-1}$

0.0204 minute$^{-1}$

0.0306 minute $^{-1}$

0.0408 minute ${ }^{-1}$

MHT CET 2024 16th May Evening Shift

MCQ (Single Correct Answer)

-0

For the reaction,

$$\mathrm{CH}_3 \mathrm{Br}_{(\mathrm{aq})}+\mathrm{OH}_{(\mathrm{aq})}^{-} \longrightarrow \mathrm{CH}_3 \mathrm{OH}_{(\mathrm{aq})}+\mathrm{Br}_{(\mathrm{aq})}^{-}$$

rate of consumption of $\mathrm{OH}_{(\mathrm{aq})}^{-}$is $\mathrm{x} \mathrm{mol} \mathrm{dm}{ }^{-3} \mathrm{~s}^{-1}$ What is the rate of formation of $\mathrm{Br}_{(9 q)}^{-}$?

$0.5 \mathrm{x} \mathrm{~mol} \mathrm{~dm}^{-3} \mathrm{~s}^{-1}$

$\mathrm{x} \mathrm{~mol} \mathrm{~dm}^{-3} \mathrm{~s}^{-1}$

$2x \mathrm{~mol} \mathrm{~dm}^{-3} \mathrm{~s}^{-1}$

$\frac{3}{2}x\mathrm{~mol} \mathrm{~dm}^{-3} \mathrm{~s}^{-1}$

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