1
GATE EE 2008
MCQ (Single Correct Answer)
+2
-0.6
The time constant for the given circuit will be GATE EE 2008 Electric Circuits - Transient Response Question 11 English
A
$$1/9$$ $$s$$
B
$$1/4$$ $$s$$
C
$$4$$ $$s$$
D
$$9$$ $$s$$
2
GATE EE 2008
MCQ (Single Correct Answer)
+2
-0.6
The ac bridge shown in the figure is used to measure the impedance $$Z.$$ If the bridge is balanced for oscillator frequency $$f=2$$ $$kHz$$, then the impedance $$Z$$ will be GATE EE 2008 Electrical and Electronics Measurement - Measurement of Resistance and A.C Bridges Question 2 English
A
$$\left( {260 + j0} \right)\,\Omega $$
B
$$\left( {0 + j200} \right)\,\Omega $$
C
$$\left( {260 - j200} \right)\,\Omega $$
D
$$\left( {260 + j200} \right)\,\Omega $$
3
GATE EE 2008
MCQ (Single Correct Answer)
+2
-0.6
A bridge circuit is shown in the figure below. Which one of the sequence given below is most suitable for balancing the bridge? GATE EE 2008 Electrical and Electronics Measurement - Measurement of Resistance and A.C Bridges Question 3 English
A
First adjust $${R_4},$$ and then adjust $${R_1}$$
B
First adjust $${R_2},$$ and then adjust $${R_3}$$
C
First adjust $${R_2},$$ and then adjust $${R_4}$$
D
First adjust $${R_4},$$ and then adjust $${R_2}$$
4
GATE EE 2008
MCQ (Single Correct Answer)
+2
-0.6
Two Sinusoidal signal $$p\left( {{\omega _1}t} \right) = A\,\sin \omega t,$$ and $$q\left( {{\omega _2}t} \right)$$ are applied to $$X$$ and $$Y$$ inputs of a dual channel $$C.R.O,$$ the lissajous figure displayed on the screen is shown below. The signal $$q\left( {{\omega _2}t} \right)$$ will be represented as GATE EE 2008 Electrical and Electronics Measurement - Cathode Ray Oscilloscope Question 2 English
A
$$q\left( {{\omega _2}t} \right) = A\,\sin \,{\omega _2}t,{\omega _2} = 2{\omega _1}$$
B
$$q\left( {{\omega _2}t} \right) = A\,\sin \,{\omega _2}t,{\omega _2} = {\raise0.5ex\hbox{$\scriptstyle {{\omega _1}}$} \kern-0.1em/\kern-0.15em \lower0.25ex\hbox{$\scriptstyle 2$}}$$
C
$$q\left( {{\omega _2}t} \right) = A\,\cos \,{\omega _2}t,{\omega _2} = 2{\omega _1}$$
D
$$q\left( {{\omega _2}t} \right) = A\,\cos \,{\omega _2}t,{\omega _2} = {\raise0.5ex\hbox{$\scriptstyle {{\omega _1}}$} \kern-0.1em/\kern-0.15em \lower0.25ex\hbox{$\scriptstyle 2$}}$$
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