1
GATE EE 2008
MCQ (Single Correct Answer)
+2
-0.6
A synchronous motor is connected to an infinite bus at $$1.0$$ $$p.u$$ voltage and draws $$0.6$$ $$pu$$ at unity power factor. Its synchronous reactance is $$1.0$$ $$pu$$ and resistance is negligible.

The excitation voltage and load angle will respectively be

A
$$0.8$$ $$pu$$ and $$36.86$$ degrees lag
B
$$0.8$$ $$pu$$ and $$36.86$$ degrees lead
C
$$1.17$$ $$pu$$ and $$30.96$$ degrees lead
D
$$1.17$$ $$pu$$ and $$30.96$$ degrees lag
2
GATE EE 2008
MCQ (Single Correct Answer)
+2
-0.6
A $$3$$-phase, $$440$$ $$V,$$ $$50$$ $$Hz,$$ $$4$$ pole, slip ring induction motor is feed from the rotor side through an auto transformer and the stator is connected to a variable resistance as shown in the figure. GATE EE 2008 Electrical Machines - Induction Machines Question 18 English

The motor is coupled to a $$220$$ $$V$$, separately excited $$d.c.$$ generator feeding power to fixed resistance of $$10\Omega .$$ Two watt-meter method is used to measure the input power to induction motor. The variable resistance is adjusted such that motor recorded
$${W_1} = 1800\,W,\,\,{W_2} = - 200\,W.$$

Neglecting all losses of both the machines, the $$dc$$ generator power output and the current through resistance $$\left( {{R_{ex}}} \right)$$ will respectively be

A
$$96$$ $$W,$$ $$3.10$$ $$A$$
B
$$120$$ $$W,$$ $$3.46$$ $$A$$
C
$$1504$$ $$W,$$ $$12.26$$ $$A$$
D
$$1880$$ $$W,$$ $$13.71$$ $$A$$
3
GATE EE 2008
MCQ (Single Correct Answer)
+1
-0.3
Distributed winding and short chording employed in AC machines will result in
A
increase in $$emf$$ and reduction in harmonics
B
reduction in $$emf$$ and increase in harmonics
C
increase in both $$emf$$ and harmonics
D
reduction in both $$emf$$ and harmonics
4
GATE EE 2008
MCQ (Single Correct Answer)
+2
-0.6
A $$230V,$$ $$50Hz,$$ $$4$$ pole, single phase induction motor is rotating in the clockwise (forward) direction at a speed of $$1425$$ $$rpm.$$ If the rotor resistance at standstill is $$7.8\,\,\Omega ,$$ then the effective rotor resistance in the backward branch of the equivalent circuit will be
A
$$2\Omega $$
B
$$4\Omega $$
C
$$78\Omega $$
D
$$156\Omega $$