1
GATE EE 2008
MCQ (Single Correct Answer)
+1
-0.3
Two $$8$$ $$A$$ $$D$$ $$C$$ $$s$$ one of single slope integrating type and other of successive approximation type. Take $${T_A}$$ and $${T_B}$$ times to connect $$5V$$ analog input signal to equivalent digital output. If the input analog signal is reduced to $$2.5V$$ the approximate time taken by the two $$ADC's$$ will respectively be
A
$${T_A},\,\,{T_B}$$
B
$${\raise0.5ex\hbox{$\scriptstyle {{T_A}}$} \kern-0.1em/\kern-0.15em \lower0.25ex\hbox{$\scriptstyle 2$}},\,\,{T_B}$$
C
$${T_A},\,\,{\raise0.5ex\hbox{$\scriptstyle {{T_B}}$} \kern-0.1em/\kern-0.15em \lower0.25ex\hbox{$\scriptstyle 2$}}$$
D
$${\raise0.5ex\hbox{$\scriptstyle {{T_A}}$} \kern-0.1em/\kern-0.15em \lower0.25ex\hbox{$\scriptstyle 2$}},\,\,{\raise0.5ex\hbox{$\scriptstyle {{T_B}}$} \kern-0.1em/\kern-0.15em \lower0.25ex\hbox{$\scriptstyle 2$}}$$
2
GATE EE 2008
MCQ (Single Correct Answer)
+2
-0.6
A $$230V,$$ $$50Hz,$$ $$4$$ pole, single phase induction motor is rotating in the clockwise (forward) direction at a speed of $$1425$$ $$rpm.$$ If the rotor resistance at standstill is $$7.8\,\,\Omega ,$$ then the effective rotor resistance in the backward branch of the equivalent circuit will be
A
$$2\Omega $$
B
$$4\Omega $$
C
$$78\Omega $$
D
$$156\Omega $$
3
GATE EE 2008
MCQ (Single Correct Answer)
+2
-0.6
A $$400$$ $$V,$$ $$50$$ $$Hz$$, $$4$$ pole, $$1400$$ $$rpm$$, star connected squirrel cage induction motor has the following parameters referred to the stator:
$$R = 1.0\,\Omega ,{X_s} = X{'_r} = 1.5\,\Omega $$ Neglect stator resistance and core and rotational losses of the motor. The motor is controlled from a $$3$$-phase voltage source inverter with constant $$V/f$$ control. The stator line-to-line voltage $$(rms)$$ and frequency to obtain the maximum torque at starting will be:
A
$$20.6\,V,\,\,2.7\,Hz$$
B
$$133.3\,V,\,\,16.7\,Hz$$
C
$$266.6\,V,\,\,33.3\,Hz$$
D
$$323.3\,V,\,\,40.3\,Hz$$
4
GATE EE 2008
MCQ (Single Correct Answer)
+2
-0.6
A $$400$$ $$V,$$ $$50$$ $$Hz,$$ $$30$$ $$hp,$$ three-phase induction motor is drawing $$50$$ A current at $$0.8$$ power factor lagging. The stator and rotor copper losses are $$1.5kW$$ and $$900$$ $$W$$ respectively. The friction and windage losses are $$1050$$ $$W$$ and the core losses are $$1200$$ $$W.$$ The air-gap power of the motor will be
A
$$23.06$$ $$kW$$
B
$$24.11$$ $$kW$$
C
$$25.01$$ $$kW$$
D
$$26.21$$ $$kW$$
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