1
GATE EE 2008
+2
-0.6
The ac bridge shown in the figure is used to measure the impedance $$Z.$$ If the bridge is balanced for oscillator frequency $$f=2$$ $$kHz$$, then the impedance $$Z$$ will be
A
$$\left( {260 + j0} \right)\,\Omega$$
B
$$\left( {0 + j200} \right)\,\Omega$$
C
$$\left( {260 - j200} \right)\,\Omega$$
D
$$\left( {260 + j200} \right)\,\Omega$$
2
GATE EE 2008
+2
-0.6
Two Sinusoidal signal $$p\left( {{\omega _1}t} \right) = A\,\sin \omega t,$$ and $$q\left( {{\omega _2}t} \right)$$ are applied to $$X$$ and $$Y$$ inputs of a dual channel $$C.R.O,$$ the lissajous figure displayed on the screen is shown below. The signal $$q\left( {{\omega _2}t} \right)$$ will be represented as
A
$$q\left( {{\omega _2}t} \right) = A\,\sin \,{\omega _2}t,{\omega _2} = 2{\omega _1}$$
B
$$q\left( {{\omega _2}t} \right) = A\,\sin \,{\omega _2}t,{\omega _2} = {\raise0.5ex\hbox{\scriptstyle {{\omega _1}}} \kern-0.1em/\kern-0.15em \lower0.25ex\hbox{\scriptstyle 2}}$$
C
$$q\left( {{\omega _2}t} \right) = A\,\cos \,{\omega _2}t,{\omega _2} = 2{\omega _1}$$
D
$$q\left( {{\omega _2}t} \right) = A\,\cos \,{\omega _2}t,{\omega _2} = {\raise0.5ex\hbox{\scriptstyle {{\omega _1}}} \kern-0.1em/\kern-0.15em \lower0.25ex\hbox{\scriptstyle 2}}$$
3
GATE EE 2008
+1
-0.3
Two $$8$$ $$A$$ $$D$$ $$C$$ $$s$$ one of single slope integrating type and other of successive approximation type. Take $${T_A}$$ and $${T_B}$$ times to connect $$5V$$ analog input signal to equivalent digital output. If the input analog signal is reduced to $$2.5V$$ the approximate time taken by the two $$ADC's$$ will respectively be
A
$${T_A},\,\,{T_B}$$
B
$${\raise0.5ex\hbox{\scriptstyle {{T_A}}} \kern-0.1em/\kern-0.15em \lower0.25ex\hbox{\scriptstyle 2}},\,\,{T_B}$$
C
$${T_A},\,\,{\raise0.5ex\hbox{\scriptstyle {{T_B}}} \kern-0.1em/\kern-0.15em \lower0.25ex\hbox{\scriptstyle 2}}$$
D
$${\raise0.5ex\hbox{\scriptstyle {{T_A}}} \kern-0.1em/\kern-0.15em \lower0.25ex\hbox{\scriptstyle 2}},\,\,{\raise0.5ex\hbox{\scriptstyle {{T_B}}} \kern-0.1em/\kern-0.15em \lower0.25ex\hbox{\scriptstyle 2}}$$
4
GATE EE 2008
+2
-0.6
A $$230V,$$ $$50Hz,$$ $$4$$ pole, single phase induction motor is rotating in the clockwise (forward) direction at a speed of $$1425$$ $$rpm.$$ If the rotor resistance at standstill is $$7.8\,\,\Omega ,$$ then the effective rotor resistance in the backward branch of the equivalent circuit will be
A
$$2\Omega$$
B
$$4\Omega$$
C
$$78\Omega$$
D
$$156\Omega$$
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