1
MCQ (Single Correct Answer)

AIPMT 2002

Which of the following has p$$\pi $$ $$-$$ d$$\pi $$ bonding?
A
NO3$$-$$
B
SO32$$-$$
C
BO33$$-$$
D
CO32$$-$$

Explanation

Electronic structure of S atom in excited state


In 'S' unhybride d- orbital is present, which will involved in bond formation with oxygen atom.

In oxygen two unpaired p- orbital is present in these one is involved in $$\sigma $$ bond formation while other is used in $$\pi $$ bond formation.

So, in SO32$$-$$, p$$\pi $$ $$-$$ d$$\pi $$ bonding present.
2
MCQ (Single Correct Answer)

AIPMT 2001

In X - H --- Y, X and Y both are electronegative elements. Then
A
electron density on X will increase and on H will decrease
B
in both electron density will increase
C
in both electron density will decrease
D
on X electron density will decrease and on H increases.

Explanation

As X and Y both are electronegative elements thus both attracts the electron density from H thus, electron density on H decreases and on X it increases.
3
MCQ (Single Correct Answer)

AIPMT 2001

In which of the following bond angle is maximum ?
A
NH3
B
NH4+
C
PCl3
D
SCl2

Explanation

Bond angle is maximum in NH4+ tetrahedral molecule with bond angle 109°.
4
MCQ (Single Correct Answer)

AIPMT 2001

Nitrogen forms N2, but phosphorus does not form P2, however, it converts P4, reason is
A
triple bond present between phosphorus atom
B
p$$\pi $$ $$-$$ p$$\pi $$ bonding is weak
C
p$$\pi $$ $$-$$ p$$\pi $$ bonding is strong
D
multiple bonds form easily.

Explanation

For strong $$\pi $$-bonding, p$$\pi $$ - p$$\pi $$ bonding should be strong. In case of P, due to larger size as compared to N-atom, p$$\pi $$ - p$$\pi $$ bonding is not so strong.

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