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1

### NEET 2016 Phase 1

Predict the correct order among the following :
A
bond pair - bond pair > long pair - bond pair > lone pair - lone pair
B
lone pair - bond pair > bond pair - bond pair > lone pair - lone pair
C
lone pair - lone pair > lone pair - bond pair > bond pair - bond pair
D
lone pair - lone pair > bond pair - bond pair > lone pair - bond pair

## Explanation

According to VSEPR theory, the repulsive forces between lone pair and lone pair are grater than between lone pair and bond pair which are further greater than bond pair and bond pair.
2

### NEET 2016 Phase 2

Among the following, which one is a wrong statement ?
A
PH5 and BiCl5 do not exist.
B
p$$\pi$$-d$$\pi$$ bonds are present in SO2.
C
SeF4 and CH4 have same shape.
D
I3+ has bent geometry.

## Explanation 3

### NEET 2016 Phase 2

The correct geometry and hybridization for XeF4 are
A
octahedral, sp3d2
B
trigonal bipyramidal, sp3d
C
planar triangle, sp3d3
D
square planar, sp3d2

## Explanation sp3d2 hybridisation (octahedral geometry, square planar shape)
4

### NEET 2016 Phase 2

The hybridizations of atomic orbitals of nitrogen in NO$$_2^ +$$, NO$$_3^ -$$  and  NH$$_4^ +$$  respectively are
A
sp, sp3 and sp2
B
sp2, sp3 and sp3
C
sp, sp2 and sp3
D
sp2, sp and sp3

## Explanation

X = $$1 \over 2$$ (VE + MA - c + a)

For $$NO^+_2$$, X = $$1 \over 2$$ (5 + 0 - 1) = 2, so sp hybridisation

For $$NO^-_3$$, X = $$1 \over 2$$ (5 + 0 + 1) = 3, so sp2 hybridisation

For $$NH^+_4$$, X = $$1 \over 2$$ (5 + 4 - 1) = 4, so sp3 hybridisation

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Class 12