The vapour pressure of two liquids P and Q are 80 and 60 torr, respectively. The total vapour pressure of solution obtained by mixing 3 mole of P and 2 mole of Q would be

A solution has a 1 : 4 mole ratio of pentane to hexane. The vapour pressures of the pure hydrocarbons at 20^oC are 440 mm Hg for pentane and 120 mm Hg for hexane. The mole fraction of pentane in the vapour phase would be

A solution of urea (mol. mass 56 g mol^$$-$$1) boils at 100.18^oC at the atmospheric pressure. If K_f and K_b for water are 1.86 and 0.512 K kg mol^$$-$$1 respectively, the above solution will freeze at

A solution containing components A and B folloes Raoult's law