AIPMT 2010 Prelims | Properties of Matter Question 63 | Physics

AIPMT 2010 Prelims

MCQ (Single Correct Answer)

-1

The total radiant energy per unit area, normal to the direction of incidence, received at a distance R from the centre of a star of radius r, whose outer surface radiates as a black body at a temperature TK is given by

$${{\sigma {r^2}{T^4}} \over {{R^2}}}$$

$${{\sigma {r^2}{T^4}} \over {4\pi {R^2}}}$$

$${{\sigma {r^2}{T^4}} \over {{R^4}}}$$

$${{4\pi \sigma {r^2}{T^4}} \over {{R^2}}}$$

AIPMT 2010 Prelims

MCQ (Single Correct Answer)

-1

Assuming the sun to have a spherical outer surface of radius r, radiating like a black body at temperature t^oC, the power received by a unit surface, (normal to the incident rays) at a distance R from the centre of the sun is
where $$\sigma $$ is the Stefan's constant.

$${{{r^2}\sigma {{\left( {t + 273} \right)}^4}} \over {4\pi {R^2}}}$$

$${{16{\pi ^2}{r^2}\sigma {t^4}} \over {{R^2}}}$$

$${{{r^2}\sigma {{\left( {t + 273} \right)}^4}} \over {{R^2}}}$$

$${{4\pi {r^2}\sigma {t^4}} \over {{R^2}}}$$

AIPMT 2009

MCQ (Single Correct Answer)

-1

A black body at 227^oC radiates heat at the rate of 7 cals/cm²s. At a temperature of 727^oC, the rate of heat radiated in the same units will be

112

AIPMT 2009

MCQ (Single Correct Answer)

-1

The two ends of a rod of length L and a uniform cross-sectional area A are Kept at two temperatures T₁ and T₂ (T₁ > T₂). The rate of heat transfer, $${{dQ} \over {dt}}$$ through the rod in a steady state is given by :

$${{dQ} \over {dt}} = {{k\left( {{T_1} - {T_2}} \right)} \over {LA}}$$

$${{dQ} \over {dt}} = kLA({T_1} - {T_2})$$

$${{dQ} \over {dt}} = {{kA\left( {{T_1} - {T_2}} \right)} \over L}$$

$${{dQ} \over {dt}} = {{kL\left( {{T_1} - {T_2}} \right)} \over A}$$

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