For vaporization of water at 1 atmospheric pressure, the values of $$\Delta $$H and $$\Delta $$S are 40.63 kJ mol$$-$$1 and 108.8 J K$$-$$1 mol$$-$$1, respectively. The temperature when Gibb's energy change ($$\Delta $$G) for this transformation will be zero, is
A
273.4 K
B
393.4 K
C
373.4 K
D
293.4 K
Explanation
We know, from Gibb's equation,
$$\Delta $$G = $$\Delta $$H – T$$\Delta $$S
When $$\Delta $$G = 0, $$\Delta $$H = T$$\Delta $$S