1
MCQ (More than One Correct Answer)

NEET 2016 Phase 1

The correct thermodynamic conditions for the spontaneous reaction at all temperatures is
A
$$\Delta $$H < 0 and $$\Delta $$S > 0
B
$$\Delta $$H < 0 and $$\Delta $$S < 0
C
$$\Delta $$H < 0 and $$\Delta $$S = 0
D
$$\Delta $$H > 0 and $$\Delta $$S < 0

Explanation

$$\Delta G = \Delta H - T\Delta S$$

If $$\Delta $$H < 0 and $$\Delta $$S > 0
   $$\Delta G = (-ve) - T (+ve)$$

then at all temperatures, $$\Delta G$$ = -ve, spontaneous reaction.

If $$\Delta $$H < 0 and $$\Delta $$S = 0
   $$\Delta G = (-ve) - T (0)$$

then at all temperatures, $$\Delta G$$ = -ve at all temperatures.

Questions Asked from Thermodynamics

On those following papers in MCQ (Multiple Correct Answer)
Number in Brackets after Paper Name Indicates No of Questions
NEET 2016 Phase 1 (1)
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