1
MCQ (More than One Correct Answer)

NEET 2016 Phase 1

The correct thermodynamic conditions for the spontaneous reaction at all temperatures is
A
$\Delta$H < 0 and $\Delta$S > 0
B
$\Delta$H < 0 and $\Delta$S < 0
C
$\Delta$H < 0 and $\Delta$S = 0
D
$\Delta$H > 0 and $\Delta$S < 0

Explanation

$\Delta G = \Delta H - T\Delta S$

If $\Delta$H < 0 and $\Delta$S > 0
$\Delta G = (-ve) - T (+ve)$

then at all temperatures, $\Delta G$ = -ve, spontaneous reaction.

If $\Delta$H < 0 and $\Delta$S = 0
$\Delta G = (-ve) - T (0)$

then at all temperatures, $\Delta G$ = -ve at all temperatures.

On those following papers in MCQ (Multiple Correct Answer)
Number in Brackets after Paper Name Indicates No of Questions
NEET 2016 Phase 1 (1)
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