1
RE-NEET 2026
MCQ (Single Correct Answer)
+4
-1

The lanthanide ion having four unpaired electrons is (Given : Atomic numbers of $\mathrm{Ce}=58, \mathrm{Nd}=60, \mathrm{~Tb}=65$ and $\mathrm{Ho}=67$ )

A

$\mathrm{Ho}^{3+}$

B

$\mathrm{Nd}^{3+}$

C

$\mathrm{Ce}^{3+}$

D

$\mathrm{Tb}^{3+}$

2
RE-NEET 2026
MCQ (Single Correct Answer)
+4
-1

The green paramagnetic species formed by heating $\mathrm{KMnO}_4$ at 513 K is

A

$\mathrm{KO}_2$

B

$\mathrm{K}_2 \mathrm{MnO}_4$

C

$\mathrm{Mn}_3 \mathrm{O}_4$

D

MnO

3
RE-NEET 2026
MCQ (Single Correct Answer)
+4
-1

Given below are two statements: One is labelled as Assertion A and the other is labelled as Reason R.

Assertion A: Generally, $3 d$ transition metals have high melting points.

Reason R: Involvement of $3 d$-electrons in addition to $4 s$-electrons in the interatomic metallic bonding.

In light of the above statements, choose the most appropriate answer from the options given below:

A

$\mathbf{A}$ is not correct but $\mathbf{R}$ is correct

B

Both $\mathbf{A}$ and $\mathbf{R}$ are correct and $\mathbf{R}$ is the correct explanation of $\mathbf{A}$

C

Both $\mathbf{A}$ and $\mathbf{R}$ are correct and $\mathbf{R}$ is NOT the correct explanation of $\mathbf{A}$

D

$\mathbf{A}$ is correct but $\mathbf{R}$ is not correct.

4
NEET 2026
MCQ (Single Correct Answer)
+4
-1
Change Language

$$ \text { Match List I with List II : } $$

List I
(Transition metal/compound/ complex)
List II
(Catalytic Role)
A. $$\mathrm{V}_2 \mathrm{O}_5$$ I. Preparation of ammonia from $\mathrm{N}_2 / \mathrm{H}_2$ mixture
B. Fe II. Polymerisation of alkynes
C. $\mathrm{PdCl}_2$ III. Preparation of $\mathrm{H}_2 \mathrm{SO}_4$ and $\mathrm{SO}_2$
D. Ni complex IV. Oxidation of ethyne to ethanal
Choose the correct answer from the options given below.
A

A-III, B-IV, C-I, D-II

B

A-IV, B-I, C-III, D-II

C

A-II, B-I, C-IV, D-III

D

A-III, B-I, C-IV, D-II

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