AIPMT 2008 | Solid State Question 34 | Chemistry

This chapter is currently out of syllabus

AIPMT 2008

MCQ (Single Correct Answer)

-1

Out of Syllabus

If $$a$$ stands for the edge length of the cubic systems: simple cubic, body centred cubic and face centred cubic, then the ratio of radii of the spheres in these systems will be respectively

$${1 \over 2}a:{{\sqrt 3 } \over 2}a:{{\sqrt 2 } \over 2}a$$

$$1a:\sqrt 3 a:\sqrt 2 a$$

$${1 \over 2}a:{{\sqrt 3 } \over 4}a:{1 \over {2\sqrt 2 }}a$$

$${1 \over 2}a:\sqrt 3 a:{1 \over {\sqrt 2 }}a$$

AIPMT 2007

MCQ (Single Correct Answer)

-1

Out of Syllabus

If NaCl is doped with 10^$$-$$4 mol% of SrCl₂, the concentration of cation vacancies will be (N_A = 6.02 $$ \times $$ 10²³ mol^$$-$$1)

6.02 $$ \times $$ 10¹⁶ mol^$$-$$1

6.02 $$ \times $$ 10¹⁷ mol^$$-$$1

6.02 $$ \times $$ 10¹⁴ mol^$$-$$1

6.02 $$ \times $$ 10¹⁵ mol^$$-$$1

AIPMT 2007

MCQ (Single Correct Answer)

-1

Out of Syllabus

The fraction of total volume occupied by the atoms present in a simple cube is

$${\pi \over {3\sqrt 2 }}$$

$${\pi \over {4\sqrt 2 }}$$

$${\pi \over 4}$$

$${\pi \over 6}$$

AIPMT 2006

MCQ (Single Correct Answer)

-1

Out of Syllabus

CsBr crystallises in a body centered cubic lattice. The unit cell length is 436.6 pm. Given that the atomic mass of Cs = 133 and that of Br = 80 amu and Avogadro number being 6.02 $$ \times $$ 10²³ mol^$$-$$1, the density of CsBr is

4.25 g/cm³

42.5 g/cm³

0.425 g/cm³

8.25 g/cm³

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